On Commuting Operator Exponentials, II
We prove that, under sufficient conditions on the spectra,
$$e^M e^N\subseteq e^N e^M\Rightarrow MN\subseteq NM,$$
where 𝑁 is an unbounded normal operator and 𝑀 is a bounded normal operator in the Hilbert space.
Volume 132, 2022
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